01/26/13 1
NOÀNG ÑOÄ DUNG DÒCH LOÛNG
M = mol/L, mg/L
[Ca2+] = 40 mg/L = ? M
[Ca2+] = 40(mg/L) / 40(g/mol) = 10-3 mol/L = 10-3 M
40(mg/L)
40(g/mol)
01/26/13 2
Söï chuyeån hoùa giöõa caùc loaïi
noàng ñoä
ct
M
M
10.d.C%
C
=
D
10.d.C%
N
=
n
N
C
M
=
01/26/13 3
Noàng ñoä phaàn trieäu khoái löôïng(ppm)
Ppm (parts per million) = µg (chaát tan)/1g (dung dòch)
= 10-6 g (chaát tan /g (dung dòch
Ñoái vôùi caùc dd nöôùc raát loaûng thì d ≈1g/ml neân:
1µg chaát/ml (dung dòch) = 1mg/l ≈ 1µg/(ml*
1g/ml)=ppm
VD [Ca2+] = 40 mg/L = ? ppm
[Ca2+] = 40 mg/L = 40 µg /ml ≈ 40 ppm
1µg /ml = 1mg/l ≈ 1ppm
1 g =
(ml* 1g/ml)
µ
01/26/13 4
Töø [A], [p] ⇒Töø [A’], [p’] ⇒
1 .
1 . β
βMY
MY
2. T, S
3. E0
1 .
1 . β
β’
’MY
MY
2. T’, S’
3. E0’
α
αA(p) =
A(p) =
[Ao]/ [A] α
αA(Z1) =
A(Z1) =
[A’]/ [A]
01/26/13 5
'MY
MY
( 2)
( 1)
Z
Y
M Z
β
βα α
=
P.69