TRU'dNG BH SU' PHAM KY THUAT TPHCM
KHOA CO KHI CHE TAO MAY
BO MON CODIENTU'
DE THI CUOI KY HOC KY I NAM HOC 2019-2020
Mon: TIN HOC TRONG KY THUAT
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M3 mnn hnc MF.TF1,14529
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Chu’ ky giam thi 1 Chu ky giam thi 2 Be so/Ma dl: 01
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Be thi co 08
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trang.
Thai gian: 70.. phut.
Dirac phep su dung tai lieu (KHONG su dung laptop).
CB cham thi thu nhat CB cham thi thu hai
So cau dung: So cau dung:
Diem va chir ky Dilm va ch& ky
Ho va ten:
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M as6SV :.....................................................................
So TT:.......................Phong thi:
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PHIEU TRA LOfI
Hiro'ng dSn tra 161 cau hoi:
Chon cau tra lai dung: Bo chon: Chon lai:
No. ab c dNo. a bcd
121
222
323
424
525
626
727
828
929
10 30
11 31
12 32
13 33
14 34
15 35
16 36
17 37
18 38
19 39
20 40
S6 hieu: BM2/QT-PBBCL-RBTV 1/2
PHANI-MATLAB (15 cau)
Cau 1: (0.25 diim)
Trong cac cau lenh Matlab sau, cau lenh nao la DUNG:
4
a. x_5 = 5
c. 5_x = 5
Cau 2: (0.25 diem)
Cho biet ket qua cua phep toan sau.
» 0 / 0
b. _x5 = 5
d. Tat ca deu dung..
a. 0.
c. NaN.
b. Inf.
d. Tat ca deu sai.
Cau 3: (0.25 diem)
Lenh close all trong Matlab co chuc nang:
a. Dong toan bo cua so lam viec
c. Dong toan bo cua so do hoa (Figure)
b. Thoat Matlab
d. Tdt ca deu sai.
Cau 4: (0.25 diem)
Trong cua so Command cua Matlab, chung ta thuc hien lenh sau:
» 2*3A2
Ket qua la:
a. 16
c. Cau lenh bao loi
b. 18
d. Tat ca deu sai.
Cau 5: (0.25 diem)
Trong cua s6 Command cua Matlab, chung ta thuc hien lenh sau:
» abs(3+4j)
Ket qua la:
a. 5
c. Cau lenh bao 16i
Cau 6: (0.25 diim)
b. 7
d. Tdt ca deu sai.
Trong Matlab, d l tlnh phep toan y = ln(x), ta su dung cau lenh sau:
a. y = ln(x)
c. y = loge(x)
b. y = log(x)
d. Tat ca deu sai.
Cau 7: (0.25 diem)
Trong cua so command cua Matlab, chung ta thuc hien lenh sau:
» a=[l 2 3];
» b=[l;l;l];
» aAb
Ket qua in ra la:
a. [1 2 3]
c. Cau lenh bao loi
b. 6
d. Tat ca deu sai.
S6 hieu: BM2/QT-PDBCL-RDTV 2/8
Cau 8: (0.25 dilm )
Trong cua so command cua Matlab, chung ta thuc hien lenh sau:
» a=[l 2 3];
» b = a ' ;
» a.*b
Ket qua in ra la:
a. 10
c. Cau lenh bao loi
b. 14
d. Tit ca dlu sai.
Cau 9: (0.25 diem)
Trong cua s6 Command cua Matlab, cho biet gia tri cua x khi chung ta thuc hien lenh sau:
» x = 0:2.5:8
a. 0 2.5 5.0 7.5
c. Cau lenh bao loi
b. 0 2 4 8
d. Tat ca deu sai.
Cau 10: (0.25 diem)
Trong cua s6 command cua Matlab, cho bi6t gia trj cua y khi chung ta thuc hien lenh sau:
» x = 0:2:6
» y = 2*sin(x)
a. Vecto 1 hang 3 cot
c. Vecto 1 hang 1 cot
b. Vecot 1 hang 4 cot
d. Cau lenh bao 16i.
Cau 11: (0.25 diim)
Cho 2 vector x = [1 2 3] va y = [1 0 0], cau lenh nao sau day la SAI:
a. pie(x) b. pie(x,y)
c. pie(y,x)
Cau 12: (0.25 dilm)
Cho vecto x co gia trj nhu sau:
» x = [1:5]
d. Khong cau lenh nao SAI.
B6 ve d6 thi sin2(x), cau lenh nao sau day la BUNG:
a. plot(sin(x)A2) b. plot( 'sin(x)A2 ')
c. fplot( 'sin(x)A2 ') d. Tat ca d6u sai.
Cau 13: (0.25 diem)
Trong cac cau lenh Matlab sau, cau lenh nao la BUNG:
a. » y = sym(x) b. » y = syms(x)
c. » y = sym( 'x ')
Cau 14: (0.25 diem)
Cho cau lenh sau:
» x= 0:10;
» plot(x,sin(x),'dk')
d. » y = syms( 'x ')
S6 hieu: BM2/QT-PBBCL-RBTV 3/2
b. Net li€n, mau den
d. Net dut, mau den
Khi chay chuang trinh, ducmg d6 thj co dang:
a. Net lien, mau xanh
c. Net dut, mau xanh
Cau 15: (0.25 di£m)
Cho cau lenh sau:
» x = [1:5]
» pIot(x,xA2)
Khi chay chuong trinh, ket qua se la:
a. Duong d6 thi co mau xanh
c. Cau lenh bao loi
PH AN II - C (25 cau)
Can 16: (0.25 diem)
d. Net dut, mau den
b. Duong do thi c6 mau do
d. Tat ca deu sai.
Cho a,b la bien s6 nguyen (int) va a = 5, b = 2, c = 2. Hay cho biet gia tri cua bieu thuc: a/b/c
a. 0.
c. 2.
Cau 17: (0.25 diem)
b. 1.
d. TSt ca d6u sai.
Cho a,b la bien s6 nguyen (int) va a = 4, b = 3. Hay cho bi6t gia tri cua bilu thuc: (++a/c)%b:
a. 0.
c. 2.
Cau 18: (0.25 diem)
b. 1.
d. Tat ca deu sai.
Cho a,b la bien so nguyen (int) va a = 4, b = 3. Hay cho bi6t gia tri cua biSu thuc: (a++*++a)%b:
a. 0. b. 1.
c. 2.
Cau 19: (0.25 diem)
d. Tat ca deu sai.
Cho a,b,c la cac bi6n s6 nguyen va a = 4, b = 2, c = 3. Hay cho biet gia tri cua bieu thuc:
(a>5)&&(b— 2)||(!(c==4)):
a. Dung/True. b. Sai/False.
Cau 20: (0.25 diem)
Cho a,b la bi6n so nguyen a = 1, b = 2. Hay cho biet gia tri cua bieu thuc: (a<3)||( a<0)&&(b>a)
a. Dung/True.
Cau 21: (0.25 dilm)
Cho doan chuong trinh nhu sau:
b. Sai/False.
char S[20] = "KIEM TRA";
int n = strlen(S);
Gia tri cua bien n la:
a. 8
c. 10
b. 9
d. Tdt ca deu sai.
S6 hieu: BM2/QT-PDBCL-RDTV
b. 9
d. Tdtcadeusai.
4/8
Cau 22: (0.25 diem)
Trong cac cau lenh sau khai bao chuoi S sau, cau lenh nao la DUNG:
b. char [10] S;
d. Tit ca diu dung.
a. CharS[10];
c. char S[10];
Cau 23: (0.25 diem)
Cho mang M dugc khai bao nhu sau:
int M[3][3];
Trong cac cau lenh sau, cau lenh nao la DUNG:
a. M = 5;
c. M[0][0] = 5;
Cau 24: (0.25 diem)
Trong cac cau lenh sau, cau lenh nao la DUNG:
a. int A[3] = {1,2,3};
c. int A[3] = {1};
D o a n c h u ffn g tr in h s au d u n g ch o c a u 2 5 ,2 6 :
char S I[10] = "12345", S2[10] = "abcde";
for (int i = 3; i>=0; i—)
{
if ( i%2 == 0) Sl[i] = S2[i+1];
else S2[i] = Sl[i+1];
}
Cau 25: (0.25 diem)
Cho biet gia tri cua chuSi SI sau khi kit thuc doan chuong trinh tren:
a. 51545 b. 52545
c. 53545 d. Tit ca diu SAI.
b. M[][] = 5;
d. Khong dap an nao dung.
b. int A[3] = {1,2};
d. Tit ca deu dung.
Cau 26: (0.25 diem)
Cho biet gia tri cua chuoi S2 sau khi ket thuc doan chuong trinh tren:
a. a3c4e b. a4c5e
c. a5c5e d. T it ca diu SAI.
D o a n c h u a n g trin h sa u d u ng cho ca u 2 7 ,2 8 :
int x = 0, y = 0;
int M[3][3] = {{1,2,3},{1,1,1},{3,2,1}};
for (int i = 0;i<3;i++)
{ for (int j = 0y<3J++)
{ if (i = j) x = x + M[i][j];
else y=y + M[i][j];
}
}
So hieu: BM2/QT-PDBCL-RDTV 5/2