TRU'CfNG DAI HQC SlT PHAM KY THUAT
THANH PH6 H 6 CHI MINH
KHOANGOAINGU*
LOOP ANH VAN KY THUAT
DE THI CU6l KY HQC KY II NAM HQC 2020
Mon: Cor Khf Dai Cirong
M5 m6n hoc: GMEN124025........................................
Be s6/M5 de: 01 Be thi c6 .. .2 trang.
Thai gian: 90 phut.
Sinh vien khong sir dung tai lieu.
Bb l
Cau hoi 1. ( 4 diem)
Hay trinh bay quy trinh cong nghe lam khuon budc 5 d6 due phoi con 15n nhu hinh ve sau?
Vat lieu: thep C45
Hinh 1
Cau hoi 2. ( 5 diem)
HSy lap quy trinh tien tho va tien tinh m |t tru ngoai phoi 080 xudng chi tilt 075 cua chi
tiet con lan nhu hinh sau?
Hinh 2
Cau hoi 3. ( 1 diem) De chi tiet con lSn co do cung cao, do mai mon cao, tdng tu6i thp lam
viec thi ta phai lam them cong viec gi dl hoan tit san phlm?
S6 hieu: BM1/QT-PDBCL-RDTV Trang: 1/1
Ghi chu: Can bg coi thi khong dupe giai thick de thi.
Chuan dau ra cua hoc phan N$i dung kiem tra
TG 1.21: C6 kh§ n&ng lap quy trinh chi tao phoi ca khl. Cau 1
[G 2.3]: C6 kha n&ng lap quy trinh gia cong ca khl 1 chi
tilt dan gian. Cau 2
[ Gl.l]: Co kha ndng giai thich cac khai niem, thuat ngu:
chuyen mon Cau 3
Ngay 11 thang 07 n&m 2020
S6 hieu: BM1/QT-PBBCL-RBTV Trang:1/1
T R U ' C J N G D A I H Q C S I / P H A M K Y T H U A T
T H A N H P H O H O C H I M I N H
K H O A N G O A I N G t T
L O f P A N H V A N K Y T H U A T
D A P A N C U O I K Y H O C K Y I I N A M H Q C 2 0 2 0
M o n : C f f K i r i D a i C m m g
M a m o n h o c : G M E N 1 2 4 0 2 5 .......................................................................................................................................................
D 6 s o / M a d e : 0 1 B e t h i c o . . . 2
....................
t r a n g .
T h o r i g i a n : 9 0 p h u t .
S i n h v i e n k h o n g s i r d u n g t a i l i e u .
B A P A N B e 1
C a u h o i 1 . ( 4 d i e m )
H a y t r i n h b a y q u y t r i n h c o n g n g h e l a m k h u o n b u a c 5 d e d u e p h o i c o n l a n n h u h i n h v e s a u ?
V a t l i e u : t h e p C 4 5
K i 6 m t r a k h u o n t r e n
K i l m t r a k h u o n d u o i
K i l m t r a h e t h o n g r o t
T i 6 n h a n h r a p k h u o n v a r o t k i m l o a i
H i n h 1
S 6 h i e u : B M 1 / Q T - P D B C L - R D T V T r a n g : 1
C a u h o i 2 . ( 5 d i e m )
H a y l a p q u y t r i n h t i e n t h o v a t i e n t i n h m a t t r u n g o a i p h o i 0 8 0 x u o n g c h i t i l t 0 7 5 c u a c h i
t i l t c o n l a n n h u h i n h s a u ?
1 . L S p p h o i
B i r o ' c 3 : T i e n m a t t r u n g o a i d > 8 0
- N a i l o n g m a m c a p , q u a y c h i a
k h o a n g u o c c h i e u k i m d i n g h o
- K e o p h o i e a c h m a m c a p
4 5 m m
- S i l t c h a t c h a u m a m c a p b a n g
e a c h q u a y c h i a k h o a m a m c a p
t h e o c h i l u k i m d o n g h o d ! k e p
c h a t p h o i
- L a y c h i a k h o a m a m c a p d e
t r e n k h a y d u n g c u
2 . L a p d a o t i e n m a t t r u
ngoai
4 . T i e n t h o
- L a p d a o t i e n m a t t r u n g o a i l e n
b o g a d a o a b a n x e d a o n g a n g
- T h a n d a o v u o n g g o c v e r i
d u e m g t a r n
- M u i d a o c a o b a n g t a r n p h o i /
t a r n t r u e c h i n h / t a r n m a m c a p
- S i e t o c d l k e p c h a t d a o
______________________
- T i e n t h o :
+ n = 3 0 0 v o n g / p h u t
+ S i = 0 , 5 m m / v d n g
+ t i = 2 m m ( c h i l u s a u c a t )
- T i e n t i n h
+ n = 3 0 0 v o n g / p h u t
+ S 2 = 0 , 3 m m / v d n g
D ' - D n ,
+ 1 2 =
-----------------------------
= 0 . 5 m m
____________
2________________
- T i e n t h o :
P h o i ® 8 0 m m
+ n = 3 0 0 v o n g / p h u t
+ S i = 0 , 5 m m / v o n g
+ t i = 2 m m ( c h i e u s a u c a t )
So dao bing mui ch6ng tim
5 . D i r a d a o v a o v i t r i
g i a c o n g t i e n t h o
- T a y t r a i q u a y b a n x a d a o d o c
( c h u y l n d o n g O x )
- T a y p h a y q u a y b a n x e d a o
n g a n g ( c h u y l n d o n g O y )
- D u a d a o v a o v i t r i c h a m m a t
S 6 h i e u : B M 1 / Q T - P B B C L - R B T V T r a n g : 2
t r u
- X o a y v o l a n g b a n x e d a o d o c
t a o c h u y e n d o n g t i n h t i e n
S ~ 0 , 5 m m / p h u t
- K h i g a n d e n v i t r i c u o i k h i d a t
c h i e u d a i L = 4 0 m m v a t a t m a y
k i e m t r a . T a d u g c d u a n g k i n h
O 7 6 m m
6 . T i e n t i n h + P h o i 0 7 6 m m
+ 1 2 = 0 , 5 m m r~L
+ S = 0 , 3 m m / p h u t
Q u a y v o l a n g b a n x e d a o n g a n g 1
/
5 v a c h d l d i e u c h i n h c h i l u s a u
c a t t 2= 0 , 5 m m ( ■
:
..................
JV
--------
1
7 . B a t m a y c h o p h o i
q u a y ( c h u y e n d o n g
c h i n h )
- Q u a y n g u g c c h i e u k i m d o n g
h o
- n = 3 0 0 v o n g / p h u t
8 . G a t c d n g a t , d u a d a i
o c 2 n u a v a o v j t r i h a p
d l t a o c h u y l n d o n g t i n h
t i l n d o c t u d o n g S i =
0 , 3 m m / p h u t ( c h u y e n
d o n g p h u )
- C h a c h o d e n k h i m u i d a o t i e n
t ^ , d u g c 1 k h o a n g L ~ 4 0 m m
- G a t c d n g a t , d u a d a i 6 c 2 n u a
v a o v i t r i l y
9 . T i t m a y , k i e m t r a B o d u a n g k i n h d a t i e n d a t
0 7 5 m m l a c o n g v i e c t i e n t i n h
h o a n t a t
C a u h o i 3 . ( 1 d i e m ) B e c h i t i e t c o n l a n c o d o c u n g c a o , d o m a i m 6 n c a o , t a n g t u 6 i t h o l a m
v i e c t h i t a p h a i l a m t h e m c o n g v i e c g i d l h o a n t i t s a n p h i m ?
+ T o i c h i t i l t c o n l a n d a t d o c u n g 5 5 H R C
+ R a m d i e u c h i n h d o c u n g v e 5 0 H R C t h e o y e u c d u
S 6 h i e u : B M 1 / Q T - P B B C L - R B T V T r a n g : 3