TRUING DAI HQC SU' PHAM KY THUAT
THANH PHO HO CHI MINH
KHOA DAO TAO CHAT LlTONG CAO
BO MON CO SO THIET KE MAY
DE THI CUOI HQC KY I NAM HOC 2023-2024
Mon: Ctr ky thuat
Ma mon hoc: ENME130620
De so/Ma de: 01 Be thi co 02 trang.
Thai gian: 90 phut. Ngay thi: 15 /12 /2023
D upe phep sic dung tai lieu: 01 ta gidy A4 v iit tay.
Cau 1: (1,5 diem)
Ba lire Fv F2, F3 tac dung len gia treo nhir tren Hinh 1. BiSt: F1 = F, F2 = 650 N va F3 = 500 N.
Chon he true toa do Oxy nhu tren hinh; T va / tuang ung la cac vector don vi cua true Ox va Oy. Hay:
a. Bieu dien cac vector lire noi tren theo cac vector don vj T, J*, F va 0;
b. Neu vector hop lire cua ba lye noi tren co do Ion FR = 600 N va hudng theo true u, tinh gia tri F va
0;
Hinh 1
Cau 2: (1,5 diem)
Cho luc co do Ion F = 80 N tac dung len thanh tai A nhu Hinh 2. Chon he true toa do Oxyz nhu tren
hinh; T ,J va k tuong ung la cac vector don vi cua true Ox, Oy va Oz. Hay:
a. Bi6u dien luc F theo cac vector don vi T,]*,k ;
b. Bieu dien vec ta mo men M0 cua luc F doi vdi diem O theo cac vector don vi T,J,k ;
c. Tlnh do ldn mo men (M0) cua luc F d6i vai diem O.
Cau 3: (1,5 di6m)
Determine the reactions at the supports A and B for equilibrium of the beam shown in Figure 3.
Cau 4: (1,5 diem)
Cho co he chiu luc, chiu lien ket va dang d trang thai can bdng nhu tren Hinh 4. Tac dung mot luc
F = 500 N len tay cdm. Bi6t tai A, B, C va D la cac lien ket khap xoay. Xac dinh luc kep thang dung
tac dung tai E. qt = 800N/m
1 „
dl
-6m-
ii
Figure 3
q2 = 600N/m
-4m-
S6 hieu: BM1/QT-PDT-RDTV/02 LSn soat xet: 02 Ngay hieu luc: 15/12/2023 Trang: 1/2
Cau 5: (2,5 diem)
Cho co ciu chuydn dong nhu Hinh 5. Tai thdi di$m khao sat nhu tren hinh ve, con trugt A dang
trugt voi van toe va gia toe tuong ung la VA = 8 m /s va aA = 3 m /s2, chot B trugt trong ranh. Biet
lien ket gitta thanh AB va con trugt A la khop xoay. Hay xac dinh:
a. Tam van t6c tuc thdi cua thanh AB; c. Van toe goc thanh AB;
b. Van toe cua diem B; d. Gia t6c goc thanh AB.
VA = 8 m/s
Cau 6: (1,5 diem)
The 50 kg wheel is subjected to a force of 50 N. If the wheel starts from rest and rolls without
slipping shown in Figure 6. Determine its angular velocity after it has rotated 10 revolutions. The
radius of gyration of the wheel about its mass center G is kG = 0,3 m.
Ghi chit: Can bo coi thi khong duoc giai thick de thi.
Chuan dau ra cua hoc phan (ve kien thirc) Noi dung kiem tra
[CLO 1.2]: Thu gon duoc mot he luc ve mot tarn thu gon,
phan tich duoc cac thanh phan phan luc lien ket (ke ca luc
ma sat) va thidt lap duoc cac phuong trinh can bang cua chat
di6m, cua vat rdn, he vat ran.
Cau 1,2
[CLO 1.2]: Tlnh duoc cac thong so dong hoc (vi tri, van toe,
gia t6c) cua vat rdn, di^m thuoc vat ran trong chuyen dong
phang.
Cau 5
[CLO 1.3]: Su dung duoc phuong phap dong luong va
phuong phap ndng luong de xac dinh duoc thong so dong
hoc cua vat rin trong chuyen dong phang duoi tac dung cua
luc
Cau 6
[CLO 2.1]: Phan ti'ch va mo hinh hoa duoc mot so co he
tlnh dinh trong co khi bang cac mo hinh tuong ung.
Cau 4
[CLO 3.1]: Su dung duoc cac thuat ngu tieng Anh ve co
ky thuat
Cau 3
Ngay ~ b thang^£nam 2023 \
Tru’O’ng bo mon /C
S6 hieu: BM1/QT-PBT-RDTV/02 Lan socit xft: 02 Ngay hieu luc: 15/12/2023 Trang: 2/2