Lecture Control system design: The performance of feedback control systems - Nguyễn Công Phương
lượt xem 3
download
This chapter presents the following content: Test input signals, performance of second – order systems, effects of a third pole & a zero on the second – order system response, the s – plane root location & the transient response, the steady – state error of feedback control systems, performance indices, the simplification of linear systems, system performance using control design software.
Bình luận(0) Đăng nhập để gửi bình luận!
Nội dung Text: Lecture Control system design: The performance of feedback control systems - Nguyễn Công Phương
- Nguyễn Công Phương CONTROL SYSTEM DESIGN The Performance of Feedback Control Systems
- Contents I. Introduction II. Mathematical Models of Systems III. State Variable Models IV. Feedback Control System Characteristics V. The Performance of Feedback Control Systems VI. The Stability of Linear Feedback Systems VII. The Root Locus Method VIII.Frequency Response Methods IX. Stability in the Frequency Domain X. The Design of Feedback Control Systems XI. The Design of State Variable Feedback Systems XII. Robust Control Systems XIII.Digital Control Systems sites.google.com/site/ncpdhbkhn 2
- The Performance of Feedback Control Systems 1. Introduction 2. Test Input Signals 3. Performance of Second – Order Systems 4. Effects of a Third Pole & a Zero on the Second – Order System Response 5. The s – Plane Root Location & the Transient Response 6. The Steady – State Error of Feedback Control Systems 7. Performance Indices 8. The Simplification of Linear Systems 9. System Performance Using Control Design Software sites.google.com/site/ncpdhbkhn 3
- Introduction Performance Performance measure, M1 measure, M2 pmin Parameter, p sites.google.com/site/ncpdhbkhn 4
- The Performance of Feedback Control Systems 1. Introduction 2. Test Input Signals 3. Performance of Second – Order Systems 4. Effects of a Third Pole & a Zero on the Second – Order System Response 5. The s – Plane Root Location & the Transient Response 6. The Steady – State Error of Feedback Control Systems 7. Performance Indices 8. The Simplification of Linear Systems 9. System Performance Using Control Design Software sites.google.com/site/ncpdhbkhn 5
- Test Input Signals (1) • If the system is stable, the response to a specific input signal will provide several measures of the performance. • But because the actual input signal of a system is usually unknown, a standard test input signal is normally chosen. • Using a standard input allows the designer to compare several competing designs. • Many control systems experience input signals that are very similar to the standard test signals. • 4 types: – Unit impulse, – Step, – Ramp, – Parabolic. sites.google.com/site/ncpdhbkhn 6
- Test Input Signals (2) r (t ) r (t ) A 2 2 0 t 0 t 1 , t , 0 A, t 0 A r (t ) 2 2 ; R( s ) 1 r (t ) ; R( s ) 0, otherwise 0, t 0 s Unit impulse Step Ramp Parabolic r (t ) r (t ) A 0 t 0 t At , t 0 A At 2 , t 0 2A r (t ) ; R( s ) 2 r (t ) ; R( s ) 3 0, t0 s 0, t0 s sites.google.com/site/ncpdhbkhn 7
- The Performance of Feedback Control Systems 1. Introduction 2. Test Input Signals 3. Performance of Second – Order Systems 4. Effects of a Third Pole & a Zero on the Second – Order System Response 5. The s – Plane Root Location & the Transient Response 6. The Steady – State Error of Feedback Control Systems 7. Performance Indices 8. The Simplification of Linear Systems 9. System Performance Using Control Design Software sites.google.com/site/ncpdhbkhn 8
- Performance of Second – Order Systems (1) R( s) n2 Y ( s) G( s) G( s) s( s 2n ) Y ( s) R( s ) ( ) 1 G( s) n2 2 R( s ) s 2n s n 2 1 n2 R( s ) Y ( s ) s s( s 2 2n s n2 ) 1 y (t ) 1 e nt sin(n 1 2 t cos1 ) 1 2 1 nt 1 e sin(n t ) sites.google.com/site/ncpdhbkhn 9
- Performance of Second – Order Systems (2) R( s) n2 Y ( s) G( s) s( s 2n ) ( ) 1 1 nt r (t ) 1 y (t ) 1 e nt sin(n 1 2 t cos1 ) 1 e sin(n t ) 1 2 1.8 y (t ) = 0.1 1.6 = 0.2 = 0.4 1.4 = 0.7 = 1.1 1.2 = 2.0 1 0.8 0.6 0.4 0.2 t 0 0 0.5 1 1.5 2 2.5 3 sites.google.com/site/ncpdhbkhn 10
- Performance of Second – Order Systems (3) R( s) n2 Y ( s) G( s) G( s) s( s 2n ) Y ( s) R( s ) ( ) 1 G( s) n2 2 R( s ) s 2n s n 2 n2 R( s ) 1 Y ( s ) 2 s 2n s n2 n y (t ) e nt sin(n 1 2 t ) 1 2 1 nt 1 e sin(n t ) sites.google.com/site/ncpdhbkhn 11
- Performance of Second – Order Systems (4) R( s) n2 Y ( s) G( s) s( s 2n ) ( ) n 1 nt r (t ) (t ) y (t ) e nt sin(n 1 2 t ) 1 e sin(n t ) 1 2 4 y (t ) = 0.10 = 0.25 3 = 0.50 = 1.1 2 1 0 -1 -2 t -3 0 0.5 1 1.5 2 2.5 3 sites.google.com/site/ncpdhbkhn 12
- Performance of Second – Order Systems (5) 1 1 nt y (t ) r (t ) 1 y (t ) 1 e nt sin(n 1 2 t cos 1 ) 1 e sin(n t ) 1 2 1.6 M pt M pt final value Percent overshoot 100% 1.4 final value Overshoot 1.2 100e / 1 2 1.0 1 0.9 1.0 0.8 0.6 Peak time Tp 0.4 n 1 2 4 Rise time Tr Settling time Ts 0.2 n Tr1 0.1 t 0 0 0.5 1 1.5 2 2.5 3 3.5 4 4.5 5 sites.google.com/site/ncpdhbkhn 13
- Performance of Second – Order Systems (5) 120 Percent overshoot Peak time 100 80 60 40 20 0 0 0.1 0.2 0.3 0.4 0.5 0.6 0.7 0.8 0.9 1 Damping ratio, sites.google.com/site/ncpdhbkhn 14
- Performance of Second – Order 1.6 Systems (6) = 10rad/s n 1.4 = 1rad/s n 1.2 1 Amplitude 0.8 0.6 0.4 0.2 0 0 1 2 3 4 5 6 7 8 9 10 Time (s) sites.google.com/site/ncpdhbkhn 15
- Performance of Second – Order Ex. Systems (7) Find K & p so that the transient response to a step should be as R( s) K Y ( s) fast as attainable while retaining an overshoot of less than 5%, s( s p ) and the settling time should be less than 4 seconds. ( ) K G( s) s( s p ) K n2 T ( s) 2 2 1 G( s) 1 K s ps K s 2n s n2 s( s p ) / 1 2 s1,2 n jn 1 2 Percent overshoot 100e 2 ) / 1(1/ 2 )2 100e (1/ 4 Ts 4 n 1 4.32% n n 1 s1,2 1 j1 n 1 1 2 p 2n 2(1/ 2) 2 2 1/ 2 K n ( 2) 2 2 2 n 2 sites.google.com/site/ncpdhbkhn 16
- Performance of Second – Order Ex. Systems (8) Find K & p so that the transient response to a step should be as R( s) K Y ( s) fast as attainable while retaining an overshoot of less than 5%, s( s p ) and the settling time should be less than 4 seconds. ( ) K 2; p 2 1.4 1.2 1 0.8 y(t) 0.6 0.4 0.2 0 0 1 2 3 4 5 6 7 8 9 10 Time (s) sites.google.com/site/ncpdhbkhn 17
- The Performance of Feedback Control Systems 1. Introduction 2. Test Input Signals 3. Performance of Second – Order Systems 4. Effects of a Third Pole & a Zero on the Second – Order System Response 5. The s – Plane Root Location & the Transient Response 6. The Steady – State Error of Feedback Control Systems 7. Performance Indices 8. The Simplification of Linear Systems 9. System Performance Using Control Design Software sites.google.com/site/ncpdhbkhn 18
- Effects of a Third Pole & a Zero on the Second – Order System Response (1) 1 T ( s) ( s 2 2 s 1)( s 1) 1.4 1.2 1 0.8 y(t) 0.6 0.4 = 2.25 = 1.5 = 0.9 0.2 = 0.4 = 0.05 = 0.001 0 0 2 4 6 8 10 12 14 Time (s) sites.google.com/site/ncpdhbkhn 19
- Effects of a Third Pole & a Zero on the Second – Order System Response (2) 1 T ( s) 2 ( s 2 s 1)( s 1) 1 Percent Settling overshoot time 2.25 0.444 0 9.63 1.50 0.666 3.9 6.30 0.90 1.111 12.3 8.81 0.40 2.50 18.6 8.67 0.05 20.0 20.5 8.37 0.45 sites.google.com/site/ncpdhbkhn 20
CÓ THỂ BẠN MUỐN DOWNLOAD
-
Lecture Fundamentals of control systems: Chapter 6 - TS. Huỳnh Thái Hoàng
103 p | 80 | 6
-
Lecture Control system design: Stability in the frequency domain - Nguyễn Công Phương
46 p | 48 | 4
-
Lecture Control system design: Frequency response methods - Nguyễn Công Phương
52 p | 57 | 2
-
Lecture Control system design: Introduction - Nguyễn Công Phương
14 p | 63 | 1
Chịu trách nhiệm nội dung:
Nguyễn Công Hà - Giám đốc Công ty TNHH TÀI LIỆU TRỰC TUYẾN VI NA
LIÊN HỆ
Địa chỉ: P402, 54A Nơ Trang Long, Phường 14, Q.Bình Thạnh, TP.HCM
Hotline: 093 303 0098
Email: support@tailieu.vn