ĐỀ THI MÔN: HÀM PHỨC VÀ PHÉP BIẾN ĐỔI LAPLACE MÃ MÔN HỌC: 1001060
THỜI GIAN: 75 PHÚT NGÀY THI: 04/06/2015
Đề thi gồm 02 trang bao gồm 10 câu hỏi trắc nghiệm và 3 câu hỏi tự luận (Được phép sử dụng tài liệu) MÃ ĐỀ THI: 1001-060-357
PHẦN TRẮC NGHIỆM LỰA CHỌN (5 ĐIỂM)
3 ze
=
2
z + + 6
18
. Hãy chọn phát biểu SAI: Câu 1: Cho hàm phức ( ) f z
) = − − là các điểm bất thường cô lập
( z z i 3
3
3 3 3
= − + và z = − − là cực điểm cấp 1 = − + là cực điểm cấp 1
i z 3 i z 3 i z 3 z = là cực điểm cấp 2
A. B. C. D. 0
z
)
( ) Re f
iy x Tìm phần thực với z = . = + . Câu 2: Cho hàm phức ( ) f z Im
( R z e e ( ) z
x
x
y e y A. B. Re e = − cos Re = cos
(
) ( ) f z
xxe
xxe
y
=
y
( (
C. D.
) ( ) f z ) ( ) f z
Re
Re = −
(
) ( ) f z
cos y
π
z
cos y
=
2
z
sin ( z 2
. Hãy chọn phát biểu ĐÚNG: Câu 3: Cho hàm phức ( ) f z
Res
2
Res
( ) f z
( ) f z
A. B. Res , 0 iπ= − và Res , 0 = và 2
(
)
(
)
Res
4
Res
2
( ) f z
( ) f z
C. D. Res , 0 π= − và Res , 0 π= − và
(
)
(
)
( ) 1 π = − f z , 2 ( ) 1 f z , 2
) 1 − ( ) 1 = f z , 2 ( ) 1 = f z , 2
=
t
t
− 1
1
−
t 2
3 2
Câu 4: Biến đổi Laplace ngược nào sau đây là SAI?
L
e
te 2
2
p
2
1 p − + 3
p
2
1
−
1
t
1 −
L
L
L A. B. − = − e 3 p p 2 1 3 2 − 3 +
e
−
=
+
( t 3 cos 3
)
( t sin 3
)
)
( t sin 2
2 3
1 2
( t 2 cos 2
)
p
4
− 2 ) − + 1
(
x
u x y là phần thực
e
C. D. − p 3 2 = + 2 p 9
ax = +
cos
.
= − e ( u x y ,
)
( ay
)
Xác định hằng số phức a sao cho ( , )
Câu 5: Cho hàm số của một hàm giải tích trên ℂ .
a = hoặc 1 a = hoặc 1
a = 2 a = − 1
A. C.
=
+
( z 2
) 1 cos
∞
∞
n
n
2
2
trong lân cận của điểm z = 0 là: Câu 6: Khai triển Laurent của hàm ( ) f z a = B. 0 D. Không tồn tại a 1 z
+
+
∑
∑
1 n 2 z
1 n 2 z
!
!
+
+
n
n
=
0
=
0
) 2 !
1 ( n 2
)
) 2 !
1 ( n 2
)
∞
∞
n
n
B. A.
+
+
n
n
n
n
2
2
− 1
2
2
− 1
∑
∑
z
1 n z !
+
n
n
=
0
=
0
2 ) ( n z ! 2
1 ) ( n z ! 2
( n
2 ) 1 !
( ) − 1 ( n 2 ( ) − 1
( ) − 1 ( n 2 ( ) − 1
Trang 1/6 - Mã đề thi 1001-060-357
D. C.
( t 2 sin 5 t
− te p
p
L : Câu 7: Tìm biến đổi Laplace )
10
−
20
t
−
2
t
−
2
L
( t sin 5
( t sin 5
2
2
te
= )
2
2
+ 20 10 L A. B. te = ) p p + + 4
(
) 29
2
)
( + p
25 +
p
10
+
2
(
)
t
t
−
2
−
2
L
( t sin 5
( t sin 5
2
2
te
= )
2
2
p
p 10 − 20 L C. D. te = ) p p − + 4
(
) 29
( ) − + 25 2
t
te 2
*
( sin 3
) u du
∫
0
: Câu 8: Tìm ảnh của hàm gốc
2
2
p
+
+
A. B.
) 9
3 )( p− 2
) 9
+
2
3 2
( 1 p
p
3 )( p− 2 1 −
( p p 1 −
2
+
C. D. + + p 2 p 3 + 9
( p p
) 9
f t có ảnh là
( )F p ,
( ) F p
t
−
3
)
u
3
L
L . Hãy chọn phát biểu ĐÚNG: Câu 9: Giả sử hàm gốc ( ) = ( ) f t
(
( ) e f u dt
t e f
)3 t
( F p p
−
3
0
∫L
=
−
3
p F = 3 ( F p
)
3
L
L
A. B.
−
3
*t
( F p
)
= ( ) te f t 3
e
= ( ) f t
p
f z có khai triển Laurent tại trong lân cận của điểm z = 0 là:
C. D.
n
2
∞
n
=
+
( ) f z
( −
) 1
n
n
2
+ 1
2
∑
n
=
0
2 ) ( n z ! 2
1 ) ( n z ! 2
.
5
I
Câu 10: Cho hàm ( )
.
( ) z f z dz
= ∫(cid:2)
z = | | 2
Tính tích phân
−
iπ 2
iπ 2 6!
iπ 2 6!
iπ 8 5!
1 4 − 5! 6!
-----------------------------------------------
B. C. D. A.
PHẦN TỰ LUẬN (5 ĐIỂM)
= 0.
( ) 0
( ) 0
y¢=
y
¢ Câu 11 (1.5 điểm). Áp dụng phép biến đổi Laplace giải phương trình vi phân sau: + với điều kiện 1t ¢ + = y y
t
2
t
2
t
+
y
e
*
( ) y u du
= + t
e
.
∫
0
=
( ) f z
3 ze - z
1.
te Câu 12 (2.0 điểm). Áp dụng phép biến đổi Laplace giải phương trình tích phân:
z = 1.
a) Khai triển Laurent hàm f trong lân cận của điểm
b) Sử dụng kết quả này tính tích phân
I
( ) f z dz
.
= ∫(cid:1)
- = z i
| 3
|
Trang 2/6 - Mã đề thi 1001-060-357
Câu 13 (1.5 điểm). Cho hàm phức
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ĐỀ THI CUỐI KỲ HỌC KỲ II NĂM HỌC 2014-2015
TRƯỜNG ĐH SƯ PHẠM KỸ THUẬT TPHCM KHOA KHOA HỌC CƠ BẢN BỘ MÔN TOÁN
Môn: HÀM PHỨC VÀ PHÉP BIẾN ĐỔI LAPLACE Chữ ký giám thị 1 Chữ ký giám thị 2 Mã môn học: 1001060
Đề số/Mã đề: 1001-060-357
Thời gian: 75 phút
Được phép sử dụng tài liệu CB chấm thi thứ nhất CB chấm thi thứ hai
Điểm và chữ ký Điểm và chữ ký Họ và tên: ....................................................................
Mã số SV: ....................................................................
Số TT:........................ Phòng thi:................................
PHẦN TRẢ LỜI CÂU HỎI TRẮC NGHIỆM 2 3 4 5 6 7 8 9 10 CÂU HỎI 1
TRẢ LỜI
PHẦN TRẢ LỜI CÂU HỎI TỰ LUẬN .........................................................................................................................................................................
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