ĐỀ THI MÔN: HÀM PHỨC VÀ PHÉP BIẾN ĐỔI LAPLACE MÃ MÔN HỌC: 1001060

THỜI GIAN: 75 PHÚT NGÀY THI: 04/06/2015

x

u x y là phần thực

e

Đề thi gồm 02 trang bao gồm 10 câu hỏi trắc nghiệm và 3 câu hỏi tự luận (Được phép sử dụng tài liệu) MÃ ĐỀ THI: 1001-060-209

ax = +

cos

,

.

( u x y

( ay

)

)

Xác định hằng số phức a sao cho ( , )

PHẦN TRẮC NGHIỆM LỰA CHỌN (5 ĐIỂM) Câu 1: Cho hàm số của một hàm giải tích trên ℂ .

a = 2

a = − 1

a = hoặc 1 a = 0

A. C.

f t có ảnh là

( )F p ,

L . Hãy chọn phát biểu ĐÚNG: Câu 2: Giả sử hàm gốc ( )

a = hoặc B. 1 D. Không tồn tại a  = ( ) ( ) F p f t  

  

( F p

)

3

L

(

 t e f  

 )3 t  

  p  F =      3

t

3

)

u

3

L

− 3 L A. B. *t  e    = ( ) f t   p

3

( F p

)

( ) e f u dt

 =  ( ) te f t 3    

( F p p

3

0

  ∫L   

  =   

L

C. D.

( t 2 sin 5 t

− te  

 )  

p

10

+

2

p

10

20

(

)

t

t

2

2

L

L

Câu 3: Tìm biến đổi Laplace :

( t sin 5

( t sin 5

2

2

 te  

 = )  

 te  

 = )  

2

2

p

p − + 4

p

A. B.

(

) 29

  ( )  − +  25 2    

p

p

10

+

20

10

20

t

2

t

2

L

L

( t sin 5

( t sin 5

2

2

 te  

 = )  

 te  

 = )  

2

2

p

p + + 4

C. D.

(

) 29

2

)

 (  + p  

 25 +   

f z có khai triển Laurent tại trong lân cận của điểm z = 0 là:

n

2

n

=

+

( ) f z

( −

) 1

n

n

2

+ 1

2

n

=

0

2 ) ( n z ! 2

1 ) ( n z ! 2

     

  .    

5

I

Câu 4: Cho hàm ( )

.

( ) z f z dz

= ∫(cid:2)

z = | | 2

Tính tích phân

iπ 2

iπ 2 6!

  1 4  −     5! 6! 

z

B. C. D. A. π8 i 5!

)

iy

x

=

.

= + .

( ) Re f

Im

iπ 2 6! ( R z e e ( ) z

x

x

y

e

y

Tìm phần thực với z Câu 5: Cho hàm phức ( ) f z

Re

e = −

cos

Re

=

cos

B. A.

(

) ( ) f z

xxe

y

xxe

y

=

( (

C. D.

) ( ) f z ) ( ) f z

Re

Re

= −

(

) ( ) f z

cos y

cos y

π

z

=

2

z

. Hãy chọn phát biểu ĐÚNG: Câu 6: Cho hàm phức ( ) f z

Res

, 0

Res

, 0

Res

Res

4

2

( ) f z

( ) f z

B. A. π= − và π= − và

(

)

(

)

( ) 1 f z , 2

) 1 − ( ) 1 f z , 2

    

  =   

sin ( z 2     

  =   

Trang 1/6 - Mã đề thi 1001-060-209

Res

2

Res

( ) f z

( ) f z

C. D. Res , 0 iπ= − và Res , 0 = và 2

(

)

(

)

( ) 1 f z , 2

( ) 1 f z , 2

    

  =   

    

 π  = −   

t

t

− 1

1

t 2

3 2

Câu 7: Biến đổi Laplace ngược nào sau đây là SAI?

L

e

te 2

2

p

1 p − + 3

2

p

1

2

1

t

− 1

L

L

L A. B. − = − e 3 p p 2 1 2 − 3 + 3    

e

=

+

( t 3 cos 3

)

( t sin 3

)

)

( t sin 2

2 3

1 2

  ( t 2 cos 2   

  )    

p

4

− 2 ) − + 1

(

         

  = − e        

C. D.     −  p 3 2  = +  2 p 9 

=

+

( z 2

) 1 cos

   1     z

n

n

2

2

trong lân cận của điểm z = 0 là: Câu 8: Khai triển Laurent của hàm ( ) f z

+

+

1 n 2 z

1 n 2 z

+

+

!

!

n

n

=

0

=

0

) 2 !

1 ( n 2

)

) 2 !

1 ( n 2

)

      

      

n

n

A. B.

+

+

n

n

n

n

2

2

− 1

2

− 1

2

z

1 n z !

+

n

n

=

0

=

0

( n

2 ) 1 !

2 ) ( n z ! 2

1 ) ( n z ! 2

  ( ) − 1   ( n 2    ( ) − 1   

      

  ( ) − 1   ( n 2    ( ) − 1   

     

t

te 2

D. C.

*

( sin 3

) u du

0

Câu 9: Tìm ảnh của hàm gốc :

2

2

p

+

+

B. A.

) 9

3 )( p− 2

) 9

3

+

+

+

2

3 2

p

( 1 p

p

3 )( p− 2 1 −

2

( p p 1 −

2

p

+

9

+

C. D.

( p p

) 9

3 ze

=

2

18

z 6 + +

. Hãy chọn phát biểu SAI: Câu 10: Cho hàm phức ( ) f z

( z z

)

0

i 3

= − − là các điểm bất thường cô lập

z = là cực điểm cấp 2 z i 3 3 z i 3 i z 3

= − + và z = − − là cực điểm cấp 1 = − + là cực điểm cấp 1

3 3 3

A. B. C. D.

¢

PHẦN TỰ LUẬN (5 ĐIỂM) Câu 11 (1.5 điểm). Áp dụng phép biến đổi Laplace giải phương trình vi phân sau: + với điều kiện 1t

= 0.

( ) 0

( ) 0

y¢=

y

¢ + = y y

t

2

t

2

t

+

y

e

*

( ) y u du

= + t

e

.

0

=

( ) f z

3 ze - z

1.

te Câu 12 (2.0 điểm). Áp dụng phép biến đổi Laplace giải phương trình tích phân:

z = 1.

a) Khai triển Laurent hàm f trong lân cận của điểm

b) Sử dụng kết quả này tính tích phân

I

( ) f z dz

.

= ∫(cid:1)

- = z i

| 3

|

Trang 2/6 - Mã đề thi 1001-060-209

Câu 13 (1.5 điểm). Cho hàm phức

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ĐỀ THI CUỐI KỲ HỌC KỲ II NĂM HỌC 2014-2015

TRƯỜNG ĐH SƯ PHẠM KỸ THUẬT TPHCM KHOA KHOA HỌC CƠ BẢN BỘ MÔN TOÁN

Môn: HÀM PHỨC VÀ PHÉP BIẾN ĐỔI LAPLACE Chữ ký giám thị 1 Chữ ký giám thị 2 Mã môn học: 1001060

Đề số/Mã đề: 1001-060-209

Thời gian: 75 phút

Được phép sử dụng tài liệu CB chấm thi thứ nhất CB chấm thi thứ hai

Điểm và chữ ký Điểm và chữ ký Họ và tên: ....................................................................

Mã số SV: ....................................................................

Số TT:........................ Phòng thi:................................

PHẦN TRẢ LỜI CÂU HỎI TRẮC NGHIỆM 2 3 4 5 6 7 8 9 10 CÂU HỎI 1

TRẢ LỜI

PHẦN TRẢ LỜI CÂU HỎI TỰ LUẬN .........................................................................................................................................................................

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