,,<br />
<br />
THI TUYTN<br />
<br />
UBND TINH THAI NGUYEN<br />
<br />
VAO LOP 10 THPT<br />
NIT hsc20l7 - 2018<br />
MON: TOAN HQC<br />
<br />
sd cra.o uuc va oAo rAo<br />
on cniNn rHUc<br />
<br />
,<br />
<br />
SWTT<br />
<br />
Thdi gian ldm bdi: I20 philt, kh6ng kA thdi gian giao<br />
(Dd tui gdm c6 01 trang)<br />
<br />
CAu 1(1,0 di6m). Kh6ng dung m6y tinh cdm tay hey giiriphuong trinh: xi<br />
<br />
Ciu<br />
<br />
2(1,0 tli6m). Cho him<br />
<br />
siS<br />
<br />
Uac rirrdt y<br />
<br />
=(2m4)*+5m-l (m<br />
<br />
lirtham<br />
<br />
+2x-8<br />
<br />
di<br />
<br />
= 0.<br />
<br />
,0,**)1.<br />
,2,<br />
<br />
Tim m d6hdm siS nghich bi6n tr€n IR. .<br />
b. Tim m d6OO ttri hnm s5 c6t trgc tung t4i.tliiSm c6 tung tIQ h -6.<br />
Cfiu 3(1,0 tli6m)' Kh6ng dtng m6y tinh cAm tay, rut ggn bi6u thrlc:<br />
a.<br />
<br />
, = (S - zJ-z + 2{s)(Jr+ 1o@)<br />
<br />
.<br />
<br />
+-<br />
<br />
L+t *6x+J-xl,f{_:.-r) nai I'=0.<br />
[Jx+3 Jx-3 x-e J(Jx+: ) [x+e<br />
<br />
cho B =(<br />
<br />
vitinh ei|tricria B khi x --12+6Ji.<br />
(mx-v=n<br />
cau 5(r,0 tli6nr). cho h€ phuong<br />
li tham si5).<br />
HEyrutggnbi6uthric.B<br />
<br />
"r* IT;;:r(m;n<br />
<br />
a. Khdng<br />
<br />
dtng m6y tfnh cim tay hay gi6i hg phuong trinh khi<br />
<br />
b. X6c itinh c6c tham sd m<br />
<br />
* --!;n<br />
2'3-1.<br />
<br />
vi n biltring hQ phuong trinh c6 nghiQm li (-Lr6).<br />
<br />
CAu 6(1,0 tli6m). Cho phuong trinh 2x2+3x-l=0. Ggi xr;xz li hai nghiQm phAn biQt cria<br />
phuong trinh. Kh6ng gi6i phuong trinh h6y tinh gi6 tri cria bi6u thric:<br />
<br />
!r*L-\.<br />
[r, \)<br />
<br />
p =z(<br />
<br />
Cflu 7(1,0 ili6m). MQt tam gi6c vu6ng c6 c4nh huyAn bing 5cm, di$n tich<br />
<br />
li<br />
<br />
6cm'. Tinh<br />
<br />
dO ddi<br />
<br />
c6c c4nh g6c vu6ng cria tam gi6c vuOng d6.<br />
<br />
Cfiu 8(1,0 tli6m). Hai dulng trOn (O) va (O') cit nhau t1i<br />
OO' . Qua ,,4 k6 tluong thang vu6ng g6c<br />
vir<br />
<br />
D.<br />
<br />
D<br />
<br />
vir B. Gqi<br />
<br />
M<br />
<br />
ldtrung di'5m cta<br />
<br />
vdi AM cit c6c dudrng trOn (O) va (O')<br />
<br />
tan tugt O C<br />
<br />
ring AC = AD<br />
tli6m). Cho dudmgtrdn (O), Auongkinh AB,ctxrg D ni*cirngphfa A6ivA ,lA<br />
<br />
Chung minh<br />
<br />
Cffu 9(1,0<br />
(<br />
<br />
A<br />
<br />
thuQc cung nh6<br />
a.<br />
<br />
fu ).Gqi E ld giao eliiim ciua AC vir BD , F ldgiao diiSm ctn AD vd BC .<br />
<br />
Tinh g6c frE khi<br />
<br />
siS<br />
<br />
r*g D<br />
<br />
do cria<br />
<br />
"*g<br />
<br />
ffi<br />
<br />
D<br />
<br />
bing 800.<br />
<br />
.<br />
<br />
khi g6c<br />
ailne ss' ,<br />
CAu 10(1,0 tli6m). Cho tam gi6c nhgn ABC (AB