NcuvEN . THI ruyrN sINH vAo Lop 10 THpr<br />
oAo r4o<br />
NAu HoC: 2Ot7 - 2018<br />
ur6N THr: roAN Hec<br />
Bn cuixH THrIc<br />
' (Dnnh cho thi sinh thi viro chuy6n<br />
<br />
:r<br />
,:<br />
<br />
UBND TINH rHAt<br />
sd crAo DUC vA<br />
<br />
crruytx<br />
<br />
To6n)<br />
<br />
Thdri gian<br />
<br />
lim biri:<br />
<br />
phft<br />
<br />
180<br />
<br />
cau 1(1,0 ili6m). Kh6ng drrng m6y tinh cam tay h6y rut<br />
<br />
(kh1ng ke thdi gian giao<br />
<br />
A=<br />
<br />
so.n<br />
<br />
di)<br />
<br />
ffl';*)<br />
<br />
Ciu2(2,0 di6m). ciei he phuong trinh sau:<br />
<br />
I*'*y'-xy+4y+l=0<br />
<br />
Ir(r- *'- y'*r*)=z(*' +t)'<br />
Cflu 3(1,0 di6m). Cho s0 tg nhi6n A =W<br />
- l8 + 2n vli n e N,z ) 2.<br />
n chilsdT<br />
<br />
Chtmg minh ring<br />
CAu 4(1,5<br />
<br />
A chia h6t cho 9.<br />
<br />
ili6m). Cho a,b,c ld c6c sti duong th6a m6n<br />
<br />
Tim giritrilonnh6t criabi6uthtc: P<br />
<br />
Ji<br />
<br />
a+b+cs<br />
<br />
-+*L+*.<br />
Jo'+t Jo'+t<br />
<br />
cffu 5(1,0 ili6m). vdi m6i sti nguy€n ducing n taky hiQu a,<br />
<br />
li<br />
<br />
si5<br />
<br />
Jc2<br />
<br />
.<br />
<br />
+t<br />
<br />
nguyEn g6n<br />
<br />
Ji *at.<br />
<br />
Vf dU: o, =l;a, =l;az = 2;aq - 2;as = 2;ao = 2;o, = 3 . Tinh gi6 tri cria t6ng:<br />
<br />
1*<br />
^s=l*f*l*...*<br />
at a2 a3<br />
dzon<br />
CAu 6(1,0 ili6m). Cho hai duong trdn t6m<br />
duong trdn<br />
<br />
(Q)<br />
<br />
duong trdn tdm<br />
<br />
ta,<br />
<br />
O<br />
<br />
ei6*<br />
<br />
l.<br />
<br />
Phan k6o ddi<br />
<br />
I<br />
azots<br />
<br />
Q vd O, nimngodi<br />
<br />
nhau. DoAn tha"g<br />
<br />
eO, c*t<br />
<br />
cta cloqn OrQ cdtdudrng trOn (q) @i B. Drmg<br />
<br />
ti€p xric ngodi vdi dudmg trdn (Q<br />
<br />
(Or) tqi C (tli6m O khdng nim tren do4n QOr).<br />
<br />
) tai O vd titip xric trong v6i duong trdn<br />
<br />
Chrmg minh rdng c6c dii:m<br />
<br />
A,B,C,D cing<br />
<br />
nim tr6n mQt duong trdn.<br />
<br />
Ciu 7Q,5 tliGm). Cho ba