a<br />
<br />
riNu rsAr NcuypN<br />
so crAo DUC vA EAo rAo<br />
<br />
UBND<br />
<br />
THr<br />
<br />
ruyrN<br />
<br />
NAna<br />
<br />
CHINH<br />
<br />
l:<br />
<br />
1Z<br />
<br />
lop ro rHpr cguytN<br />
<br />
Hec<br />
<br />
zotT -<br />
<br />
wION THI:<br />
Thdi<br />
<br />
CAu<br />
<br />
srNn<br />
<br />
gian:<br />
<br />
180<br />
<br />
2otr<br />
<br />
v4T Lrf<br />
<br />
philt (kh6ng<br />
<br />
ke thdi gian giao<br />
<br />
di)<br />
<br />
AiOml<br />
<br />
Thanh AB tt6ng ch6t, titit diQn l5cm.<br />
<br />
a. Th6u kinh trOn ld th6u<br />
<br />
kinh gi, 2 in..htr6n<br />
<br />
dich chuy6n AB rheo<br />
<br />
li thqt hay 6o? Vi sao?<br />
<br />
b. Hdy tim ti6u c1r cta th6u kinh bing ph6p dpng hinh.<br />
<br />
Ciu 5: (2,5 ili6m)<br />
Cho m4ch diQn nhu hinh.vE 2.<br />
mQt hiQu diQn<br />
RMN<br />
trcv<br />
<br />
:<br />
<br />
th6<br />
<br />
20(>, Rr<br />
<br />
URs<br />
<br />
:<br />
<br />
Dlt vdo hai<br />
<br />
dAu cua do4n m4ch<br />
<br />
18V. Bi6n trd R5 c6 diQn tro toan phAn<br />
<br />
: 2 fi ; ddn c6 diQn trd Rp : 2Q vdn k6 c6 diQn<br />
<br />
r6t kvn vd ampe kti c6 diQn tr6 nh6 khdng ctring ke.<br />
1. DiAu chinh con ch4y<br />
<br />
C d0 ampe kO chi 1A.<br />
<br />
a.Xbcilinh vi tri con ch4y C.<br />
b. Tim s6 chi v6n kti khi d6.<br />
c. Bi6t ddn s6ng binh thucrng. Tim c6ng su6t dinh mric<br />
<br />
2. Pheidi chuy6n con chay C dtln vi tri nio<br />
Gi6 tri lon nh6t 6y bang bao nhi6u?<br />
<br />
dC c6ng su6t<br />
<br />
cta ddn.<br />
ti6u thp tr6n bi6n tro dat. giittri lon ntr6tZ<br />
<br />
3. gi6t ddn chiu dugc hiQu diQn thi5 t6i da la 4,8V. Hoi con ch4y C chi dugc dich chuyiSn trong<br />
khoing ndo cria bitin tr& a6 aen kh6ng bi ch6y?<br />
<br />
Cflu 6: (1,5 tli6m)<br />
MQt hgc sinh dung mQt ampe kE c6 diQn tr