![](images/graphics/blank.gif)
Exponential diophantine equation
-
In this paper, we prove the solutions of the exponential Diophantine equation 2x − 3y = z2 where x, y and z are non-negative integers. To find the solution, Catalan ’s conjecture and division algorithm congruence were applied. The result indicates that the equation has three solutions (x, y, z) including (0, 0, 0), (1, 0, 1) and (2, 1, 1).
4p
trinhthamhodang9
10-12-2020
11
2
Download
-
Lifting The Exponent Lemma is a powerful method for solving exponential Diophantine equations. It is pretty well-known in the Olympiad folklore though its origins are hard to trace. Mathematically, it is a close relative of the classical Hensel’s lemma in number theory (in both the statement and the idea of the proof). In this article we analyze this method and present some of its applications.
12p
lilymimi0404
26-08-2015
50
5
Download
-
Annals of Mathematics This is the first in a series of papers whereby we combine the classical approach to exponential Diophantine equations (linear forms in logarithms, Thue equations, etc.) with a modular approach based on some of the ideas of the proof of Fermat’s Last Theorem. In this paper we give new improved bounds for linear forms in three logarithms. We also apply a combination of classical techniques with the modular approach to show that the only perfect powers in the Fibonacci sequence are 0, 1, 8 and 144 and the only perfect powers in the Lucas sequence are 1...
51p
noel_noel
17-01-2013
46
7
Download
-
Part I Formalisms for Computation: Register Machines, Exponential Diophantine Equations, & Pure LISP 19 21 In Part I of this monograph, we do the bulk of the preparatory work that enables us in Part II to exhibit an exponential diophantine equation that encodes the successive bits of the halting probability . In Chapter 2 we present a method for compiling register machine programs into exponential diophantine equations. In Chapter 3 we present a stripped-down version of pure LISP.
0p
xuongrong_battien
24-10-2011
46
2
Download
CHỦ ĐỀ BẠN MUỐN TÌM
![](images/graphics/blank.gif)