Đề thi HSG môn Hóa học lớp 9 năm 2017-2018 - Phòng GD&ĐT Thái Nguyên

UBND THANH PH6<br /> <br /> pnoNc<br /> <br /> THA NGLIYEN<br /> <br /> rci.<br /> <br /> cno Duc vADAo T4o<br /> on cuiNn rHrlc<br /> <br /> uu<br /> <br /> cHeN Hec srr\H Gror LoP<br /> Nim hgc 20L7 -2018<br /> vr6u: HoA Hoc<br /> <br /> 9<br /> <br /> Thdi gian tdm bdi: t 50 phtit, kh)ng ke thdt gian giao d€<br /> <br /> Ciu<br /> <br /> 1 (2,0 di€m). Hqrp cfr6t X c6 c6ng thric phdn ttr AB* (x < 4) dugc t4o ndn tir hai nguy€n t6<br /> A, B. T6ng sd proton trong phdn tt AB* b[ng 10. Tim c6ng thric phdn tri cria AB*.<br /> <br /> Cia2 (5,0 di€m)<br /> l. X6c dinh c6ng thric h6a hoc cria A, D, E, G, L, M, Q, R, T vd vi6t c6c phucrng trinh h6a hgc<br /> xhy ra (ghi rO di6u kiQn ph6n rmg).<br /> <br /> D<br /> VM<br /> <br /> Q)> E<br /> te)<br /> <br /> ) 'Q<br /> <br /> (3)><br /> (ro)<br /> <br /> G<br /> <br /> (4)><br /> <br /> --u\o<br /> |<br /> <br /> > R<br /> <br /> L<br /> <br /> (t) >A<br /> <br /> ttt) j T<br /> I<br /> <br /> A ld hqp ch6t cta kim lo4i ki6m.<br /> 2. Hoittan37,45 gam h6n hqp X g6m CaCl2,BaCl2vdo nu6c tao thdnh dung dich A. Cho toan b0<br /> dung dlch Atdc dpng vdi 0,5 lit dung dich Na2CO3 lM th6y xu6t hiQn ktit tua.<br /> a.Hdy chring t6 ring h6n hqp X tan h6t.<br /> b. N6u cho 3,745 gam X t6c dpng vdi lugng du dung dich AgNO3 thi thu dugc 7,175 gam ki5t<br /> BiCt<br /> <br /> t:ira.Xirc dinh phAn trdm khdi lugng m6i mu6i c6 trong X.<br /> c. Tinh khOi tuqng Na2CO3 du.<br /> Ciu 3 (5,0 di€m)<br /> 1. BAng phucrng ph6p hori hgc hdy phdn bi6t 4 kim lopi Ba, Cu, Ag,<br /> nhdn. Vi€t phuong trinh h6a hgc c'ha cfrc ph6n ungxhy ra.<br /> <br /> Mg tlpg trong 4 lq m6t<br /> <br /> 2. Ldy 93,9 gam h6n hgrp X g6m Fe3Oa vd A1. Nung h6n hgp X trong m6i trucrng khdng c6<br /> kh6ng khi. Sau khi ph6n ring xiy ra hodn todn thu dugc h6n hg'p Y. Chia Y ldm 2 phl'n:<br /> PhAn l: Cho t6c dpng v6i dung dich NaOH du thu dugc 0,6721it khi (ttktc).<br /> PhAn 2: Cho t6c dpng vdi dung dich HCI du thu dugc 18,816 lit khi (dktc).<br /> a. Tinh khOi luqng m6i pfrAn.<br /> b. Tinh khOi tuqng m6i ctr6t c6 trong h6n hqp X.<br /> C0u 4 (3,0 di€m)<br /> . H6n 4qp X g6m C.H, (A) vd.H2. Nrng n6.ng X vdi ch6t xric t6c Ni thu dugc khf Y duy<br /> nhat. Ti kh6i hoi c0a Y so vdi Hz g6'p 2 l.6inti kh6i hoi cria X so v6i H2.<br /> O6t chay hodn todn mQt luqng kh6c khi Y,h6rp thp todn bQ s6n phAm ch6y vdo dung dfch<br /> Ca(OH)2 thu dugc l0 gam k6t tria vd dung dich Z, dung dich ndy c6 t t Oi t.tqng tdng 25,i gam<br /> so vdi dung dfch ban dAu. Khi th0m vdo dung dichZ mQt lugng KOH du thu Auqc 2O ga- k6t<br /> tta nta. X6c dinh c6ng thric phdn tri cria Y, A.<br /> Cffu 5 (5,0 di€m)<br /> 1. Cho- 32 gambQt cl6ng kim lopi vdo binh chria 500 ml dung dich AgNO3 lM. Khu6y dAu h6n<br /> hqp d0 ph6n ring xhy ra. Sau mQt thoi gian ph6n ring, thu dugc h5n hqp cdc ch6'rt r6n X cdn<br /> n{ng62,4gam vd dung dich Y. Tinh n6n! dQ mol o0a"J6cctr6t tiong O""g dich Y.<br /> 2.H6n hqp X gdm Al2O3, Fe2O3, CuO. OC nOa tan hodn toin 4,22 gam h6n hcr,p X cdn vira dri<br /> 800 ml dung dich HCI 0,2 M. Lay 0,08 mol h6n hqp X cho t6c dr,rng voiH2 duth6y tao ra 1,8<br /> gam H2O. Vit5t phucmg trinh h6a hgc cua circ phdnring xiy ra vd tinh thdnh phAn X vC t